0.008^(2x-1)+5(-3/2)=125

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Solution for 0.008^(2x-1)+5(-3/2)=125 equation: 



0.008^(2x-1)+5(-3/2)=125

We move all terms to the left:

0.008^(2x-1)+5(-3/2)-(125)=0

determiningTheFunctionDomain
0.008^(2x-1)-125+5(-3/2)=0

We multiply parentheses

0.008^(2x-1)-125-3/2*5=0

We multiply all the terms by the denominator


(0.008^(2x-1))*2*5-3-125*2*5=0

We add all the numbers together, and all the variables

(0.008^(2x-1))*2*5-1253=0

We move all terms containing x to the left, all other terms to the right

(0.008^(2x-1))*2*5=1253

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